Use the three steps to solve the problem. Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have? { a0quarters, a1dimes }
Accepted Solution
A:
d = q + 10 10d + 25q = 345 cents ---- Substitute for "d" and solve for "q"; 10(q+10) + 25q = 345
35q + 100 = 345 35q = 245 q = 7 (# of quarters) --- Since d = q+10, d = 17 (# of dimes) ================ Cheers, Stan H.